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NumPy: Counting a Subarray

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Data Wrangling
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Difficulty: 2 | Problem written by bilaldadanlar

Educational Resource: https://cs231n.github.io/python-numpy-tutorial/


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Write a function that counts how many times the second array pattern (pattern) exists in the first array (arr) and returns the number of occurrences.

Bonus points if you do not use a for loop or list comprehension.

Sample Input:
<class 'numpy.ndarray'>
arr: [0 1 1 1 2 2 2 1 1 3 3 3]
<class 'numpy.ndarray'>
pattern: [1 1]

Expected Output:
<class 'int'>
3

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Comments
Jump to comment-93
ariel • 7¬†months ago

0

Probably my solution is not well optimized but atleast i've make it work. Feel free to give advice. TIA

matched = 0
    for x in range(len(arr) - (len(pattern) - 1)):
        match = np.array([arr[x+i] for i in range(len(pattern))])
        comparison = match == pattern
        if comparison.all():
            matched += 1

 

Ready.

Input Test Case

Please enter only one test case at a time
numpy has been already imported as np (import numpy as np)