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Spearman's Rank Correlation Coefficient

Unsolved
Prob. and Stats

Difficulty: 1 | Problem written by Junaid Ahmed
A quantitative metric of the linearity of a relation between two datasets is the Spearman rank-order correlation coefficient:

\(r_{s} = 1 - \frac{6\sum d_{i}^{2}}{n(n^{2}-1)}\)

d is the difference between the two data points

n is the total number of observations

Write a Python function to implement the Spearman rank-order correlation coefficient.

Input

d, n

Output 

Correlation coefficient

 

Sample Input:
<class 'float'>
d1: 0.2
<class 'float'>
d2: 0.4
<class 'float'>
d3: 0.5
<class 'int'>
n: 2

Expected Output:
<class 'float'>
0.55

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Comments
Jump to comment-111
uozcan12 • 5 months, 3 weeks ago

0

I applied this and I've got 0.55 but expected score seems 0.66. But what should I do?

#!/usr/bin/python3


# Please do not change the below function name and parameters
def sR(d1,d2,d3,n):
    d_square_sum = d1**2 + d2**2 + d3**2
    divided_by = n*((n**2)-1)
    division_part = (6*d_square_sum)
    return 1-(division_part/divided_by)

 

Jump to comment-161
jdy33 • 2 months, 3 weeks ago

1

I think it should be 0.55 though

Ready.

Input Test Case

Please enter only one test case at a time
numpy has been already imported as np (import numpy as np)